Unmarshaling epoch timestamp into time.Time

Running Decode() with this struct produces an error with the 'timestamp' column:

type Metrics struct {
        Id        int       `orm:"column(id);auto"`
        Name      string    `orm:"column(name);size(255);null" json:"metric_name"`
json:"lon"`
        Timestamp time.Time `orm:"column(timestamp);type(datetime)" json:"timestamp;omitempty"`

}

The error:

 parsing time "1352289160" as ""2006-01-02T15:04:05Z07:00"": cannot parse "1352289160" as """

How can I parse it into a time.Time value?

Thank you

1 answer

  • answered 2017-01-11 14:20 ain

    If you're okay to have the timestamp as unix time (I assume that what it is) just declare the field as int64, ie

    type Metrics struct {
        ...
        Timestamp   int64   `orm:"column(timestamp);type(datetime)" json:"timestamp;omitempty"`
    }
    

    You can then convert it to Go's Time type with

    var m Metrics 
    ...
    When := time.Unix(m.Timestamp, 0)
    

    Another option is to write custom UnmarshalJSON handler for the Metrics type:

    func (this *Metrics) UnmarshalJSON(data []byte) error {
        var f interface{}
        err := json.Unmarshal(data, &f)
        if err != nil { return err; }
        m := f.(map[string]interface{})
        for k, v := range m {
            switch k {
            case "metric_name": this.Name  = v.(string)
            case "timestamp": this.Timestamp = time.Unix(int64(v.(float64)), 0)
            ...
            }
        }
    }
    

    Then you have proper time.Time value in struct which makes working with it easier.