How to check if quotient is an integer? C++

I'm a beginner and I am looking for a way to check if a quotient in C++ is an integer.

For example:

int a;
double b;
cin >> a;
b = a / 4;

How do I know that b is not an integer (something like 5/4=1.25)?

5 answers

  • answered 2018-03-11 13:46 Lightness Races in Orbit

    You don't need to check whether b is an integer, because it always will be. You declared it int.

    Furthermore, because both a and 4 are also integers, a/4 is integer division, so even the expression can never be fractional.

    If you fix all of that, one way to see whether a floating-point value represents a whole number is to compare its original value with one deliberately truncated to an integer:

    foobar == static_cast<int>(foobar)

    However, as with any floating-point operations this is potentially susceptible to rounding errors so you would need to be quite a bit more specific with your general requirements.

    In the particular case shown, it would be much simpler to check modulo instead: 5 % 4 is not zero, so 5/4 is not whole.

  • answered 2018-03-11 13:46 Ron

    Before the edit:

    Your a and b variables are of type int as you declared them as such. They will remain of type int no matter the values you try to supply to them via the standard input. The type and a result of the a / 4 expression is also an int because all operands are integers involved in integer division.

    After the edit:

    If b is declared to be of type double it will remain of type double but will receive the cut-out result of an integer division as a / 4 is of type int. So if all operands are integers the result of an arithmetic expression will also be an integer. To make it of type double cast one of the operands to double:

    double b = static_cast<double>(a) / 4;


    double b = a / 4.;

  • answered 2018-03-11 13:46 kubaklamca

    You can check if size of this variable equals the size of an integer by calling function sizeof(). But you have to know that float has the same size that int have (4 bites). Here you have table with sizes of different type variables

  • answered 2018-03-11 13:46 datenwolf

    In languages like C when declaring a variable of an integer type, the value therein always will be an integer. However I guess what you're asking is, how to check if the result of a computation is a integer value. If you're doing arithmetic with integer types the most naive to understand way to do this, is to perform the inverse operation and test if the result matches the original input.

    EDIT If both operands are of integer type (as before the question edit), then you can do this:

    b = a / 4;
    if( b*4 == a ){
        cout << "a/4 is integer";

    However there are other ways to do this. For example using the remainder operator % (often confused with modulo – or rather a misnormer). On many CPU architectures the operation performing a division also gives the remainder. This

    b = a / 4;
    if( b%4 == 0 ){
        cout << "a/4 is integer";

    will be close to optimal, because a single CPU instruction will perform both computations (over the first two lines) and the comparision will usually test for a special flag set by the division operation if no remainder was left.

    *However if floating point arithmetic enters the pictures (as how after the question edit), things become a little bit more troublesome. You no longer can do the inversion test, because floating point arithmetic is imprecise¹.

    If all you're interested in is the remainder/modulo, your best bet is using the fmod function and then testing if the result is within the margin of precission error epsilon.

    if( DBL_EPSILON > fmod(a, 4) ){
            cout << "a/4 is integer (within double floating point precision)";

    If you're in need of both quotient and remainder then my preferred method is to truncate and subtract (which is usually faster):

    double b = a/4.;
    double b_r = b - trunc(b);
    if( DBL_EPSILON > fabs(b_r) ){
            cout << "a/4 is integer (within double floating point precision)";

    1: for the majority of numbers involved; there's a set of numbers, which when used in floating point arithmetic operations will yield exact results. But this is only a small subset of all the numbers representable by floating point.

  • answered 2018-03-11 13:46 einpoklum

    As other answers suggest, if you assign the division to a float you'll be getting an integer value always, since in C++ (and most languages) integer division results in an integer.

    In fact, you don't even need b to be a float. You can do one of the following:

    Use the modulo operator <- recommended

    int a;
    std::cin >> a;
    if (a % 4 == 0) { /* do something */ }

    Use a divisor-specific divisibility test

    int a;
    std::cin >> a;
    if (a & 0x11 == 0) { /* do something */ }

    An integer is divisible by 4 if its least-significant 2 bits are 0. But, in fact, the compiler will probably optimize the previous test to this one.

    Multiply the integral quotient

    If you intended to use a/4 anyway, try:

    int a;
    std::cin >> a;
    auto b = a / 4; /* b is an int... */
    if (b * 4 == a) { /* do something */ }

    This isn't very useful for the case of a fixed divisor; but if it hadn't been fixed, you might do:

    int a;
    std::cin >> a;
    std::cin >> c;
    auto b = a / c;
    if (b * c == a) { /* do something */ }